(Bash): Command to generate random number

Sometimes, we are programming some script in Bash …. and we need (for some reason) to generate some random number.

For that you can program an entire application (or function ...) yes, but ... curiously our system has already done that 😀

In a terminal, type the following and press [enter]:

echo $ RANDOM

... a number will appear, they do the same thing again and another number appears, and so on 🙂

What it does is show you a random number (any) between 0 and 32768 (integer, that is, without a comma).

If you need it to be a random number, but between 0 and ... let's say 100, you can put that limit on it 😀

echo $ (($ RANDOM% 100))

The same, another example ... if you want it to be a number between 0 and 29 it would be:

echo $ (($ RANDOM% 29))

Is it understood not? 😀

If they will use it in a bash script they are doing, to assign the generated value (a random number) to a variable it would be:

VARIABLE = `echo $ (($ RANDOM))`

Well, this is it, I don't know about you ... but I know that it will be useful to me at some point hahaha.

regards


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  1.   Oscar said

    Well, I've been testing it and it only returns a 4-digit number, how can I make it bigger?
    Very interesting tip, thank you.

    1.    KZKG ^ Gaara said

      Returns a number between 0 and 32768, I have not been able to get larger numbers.

  2.   josue said

    and can it generate exadecimals ????

  3.   ravens said

    VARIABLE = `echo $ (($ RANDOM))`

    That works but is not optimal, for the simple reason that RANDOM is a variable and you can do:
    variable = $ RANDOM
    and that's it! do not run echo in a terminal aprte (which is what you are doing)

    1.    KZKG ^ Gaara said

      Yes, obviously it can be achieved like this… the only difference is that later, to see the number that the variable took (since the user is not a guesser), it would be necessary to do an echo…. and in the end, what I do here is simply do the echo (so that the user sees what number is taken) from the beginning.

      Do I make myself understood? 🙂

  4.   Wuilmer bolivar said

    Another way to generate a random number, although this time it would be this command:

    date "+% N" | cut -c 9

    That would give us the date in nanoseconds with 9 digits. If we want a single digit, then you put the "cut -c 9" (the last digit is always more random because it is the smallest of the number). If we want 2 figures then we put the "cut - c 8,9". If we want three figures then "cut -c 7-9" (we start using the hyphen).

    The only bad thing about this is if we want to get many random numbers in a row in a short time, because this is a random number based on a date with its time. That is, if we make a for with that command we can see that:

    $ for i in `seq 1 1 500`; do date "+% N"; done

    ...
    ...
    ...

    308311367
    310807595
    313273093
    315725181
    318186139
    320671403
    323360117
    325733353
    328335462
    330694870
    333259893
    335858999
    338375622
    340798446

    ...
    ...
    ...

    I think it's clear right? The figures on the left are more similar in a short space of time, of course, and those on the right are more “random”.

  5.   black eye said

    mmm…. I liked it, I have a mini script, it is painted to generate random numbers, thanks.

  6.   G. said

    It serves .. and a lot ..
    especially if you are programming an interface in bash with password, security, etc, etc, etc haha.
    Excellent aprote.

  7.   José Antonio Followed Bent said

    Hey.
    First of all, of course, congratulations on this excellent website, which I have been following for a long time.
    And secondly, make a small note to this entry:
    When limiting is done like this:

    echo $ (($ RANDOM% 10))

    Actually, what you order the interpreter is that your generated number is always the modulus% (remainder of the division) of the subsequent number, in this example, 10.
    Any number divided by 10 will never give as a remainder something greater than the divisor itself.
    The problem is that it will not give the same number either, because a division by 0 is not logical for the interpreter.

    This means that echo $ (($ RANDOM% 10) will give results between 0 and 9, but never 10.
    The solution to this conflict is to add one to your limit, so that the same number falls within the random range.

    echo $ (($ RANDOM% 11))

    This will give results between 0 and 10.

    A greeting.

  8.   Ammiel said

    Hello, I was just building something like this, but I ran into a problem.

    I want to make 6 different numbers from 00 to 45 but not repeat them.

    echo $(($RANDOM%46)) $(($RANDOM%46)) $(($RANDOM%46)) $(($RANDOM%46)) $(($RANDOM%46)) $(($ RANDOM%46))

    EX: 17 33 16 36 45 27

bool (true)